Respuesta :
Answer: The rate law of the reaction is [tex]\text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2[/tex]
Explanation:
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:
[tex]2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)[/tex]
Rate law expression for the reaction:
[tex]\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b[/tex]
where,
a = order with respect to [tex]HgCl_2[/tex]
b = order with respect to [tex]C_2O_4^{2-}[/tex]
Expression for rate law for first observation:
[tex]3.2\times 10^{-5}=k(0.164)^a(0.15)^b[/tex] ....(1)
Expression for rate law for second observation:
[tex]2.9\times 10^{-4}=k(0.164)^a(0.45)^b[/tex] ....(2)
Expression for rate law for third observation:
[tex]1.4\times 10^{-4}=k(0.082)^a(0.45)^b[/tex] ....(3)
Expression for rate law for fourth observation:
[tex]4.8\times 10^{-5}=k(0.246)^a(0.15)^b[/tex] ....(4)
Dividing 2 from 1, we get:
[tex]\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2[/tex]
Dividing 2 from 3, we get:
[tex]\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1[/tex]
Thus, the rate law becomes:
[tex]\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2[/tex]
The rate law of the reaction is; Rate = k[HgCl2][C2O4-2]2-
In this case, we have the reaction; 2 HgCl2(aq) + C2O42-(aq) 2 Cl -(aq) + 2 CO2(g) + Hg2Cl2(s). The table that shows the rate of reaction at various concentrations is shown;
Let a be the order in terms of HgCl2
Let b be the order in terms of C2O4^2-
So;
2.9x10^-4 = k(0.164 )^a (0.45)^b ---- (1)
1.4x10^-4 = k(0.082)^a (0.45)^b ---- (2)
Dividing (1) by (2)
2.9x10^-4/1.4x10^-4 = k(0.164 )^a (0.45)^b/k(0.082)^a (0.45)^b
2 = 2^a
The reaction is first order with respect to HgCl2
Again;
3.2x10^-5 = k(0.164)^a (0.15)^b ---- (1)
2.9x10^-4 = k(0.164)^a (0.45)^b ---- (2)
Dividing (2) by (1)
2.9x10^-4/3.2x10^-5 =k(0.164)^a (0.45)^b /k(0.164)^a (0.15)^b
9 = 3^b
b = 2
The reaction is second order with respect to C2O42-
The rate law of the reaction is; Rate = k[HgCl2][C2O4-2]2-
Learn more about rate law: https://brainly.com/question/14779101
