The weight of an organ in adult males has a​ bell-shaped distribution with a mean of 340 grams and a standard deviation of 30 grams. Use the empirical rule to determine the following. ​(a) About 99.7​% of organs will be between what​ weights? ​(b) What percentage of organs weighs between 280 grams and 400 ​grams? ​(c) What percentage of organs weighs less than 280 grams or more than 400 ​grams? ​(d) What percentage of organs weighs between 250 grams and 400 ​grams?

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Answer:

a) 99.7% of the organs will be between 250 and 420 grams.

b) 95% of the organs weighs between 280 grams and 400 grams.

c) 5% of the organs weighs less than 280 grams or more than 400 grams.

d) 97.5% of the organs weighs between 250 grams and 400 grams.

Step-by-step explanation:

The mean value of the weight of an organ is 340 grams and the standard deviation is 30 grams, so [tex]\mu = 340, \sigma = 30[/tex].

(a) About 99.7​% of organs will be between what​ weights?

The Empirical Rule states that 99.7% of the values of X of a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] belong to the following interval

[tex]\mu - 3\sigma \leq X \leq \mu + 3\sigma[/tex]

We have that [tex]\mu = 340, \sigma = 30[/tex], so:

[tex]\mu - 3\sigma \leq X \leq \mu + 3\sigma[/tex]

[tex]340 - 3(30) \leq X \leq 340 + 3(30)[/tex]

[tex]250 \leq X \leq 420[/tex]

99.7% of the organs will be between 250 and 420 grams.

(b) What percentage of organs weighs between 280 grams and 400 ​grams?

280 grams is 2 standard deviations below the mean.

400 grams is 2 standard deviations above the mean.

The Empirical rule states that 95% of the weights of the organs are between 2 standard deviations of the mean, so

95% of the organs weighs between 280 grams and 400 grams.

(c) What percentage of organs weighs less than 280 grams or more than 400 ​grams?

95% of the organs weighs between 280 grams and 400 grams. This means that 5% of the organs weighs less than 280 grams or more than 400 grams.

​(d) What percentage of organs weighs between 250 grams and 400 ​grams?

250 grams is 3 standard deviations below the mean.

The Empirical rule states that 50% of the weights are above the mean, and 50% are below. Of those that are below, 100% weights at least 3 standard deviations below the mean.

400 grams is 2 standard deviations above the mean.

Of the values that are above the mean, 95% of them are at most 2 standard deviations above the mean.

So:

[tex]P = 0.5 + 0.95(0.5) = 0.5 + 0.475 = 0.975[/tex]

97.5% of the organs weighs between 250 grams and 400 grams.

You can use the empirical rules for probability related to normal distribution to get the needed percentage.

The answers are

  • About 99.7​% of organs will be between 250 and 430
  • 95% organs weighs in between 280 grams and 400 grams
  • 5% percentage of organs weighs less than 280 grams or more than 400 ​grams
  • Percentage of organs weighs between 250 grams and 400 ​grams is 97.35% approximately.

What is empirical rule for normal distribution?

According to the empirical rule, also known as 68-95-99.7 rule, the percentage of values that lie within an interval with 68%, 95% and 99.7% of the values lies within one, two or three standard deviations of the mean of the distribution.

We can write it symbolically as:

[tex]P(\mu - \sigma < X < \mu + \sigma) = 68\%\\P(\mu - 2\sigma < X < \mu + 2\sigma) = 95\%\\P(\mu - 3\sigma < X < \mu + 3\sigma) = 99.7\%[/tex]

where we had [tex]X \sim N(\mu, \sigma)[/tex]

where mean of distribution of X is [tex]\mu[/tex]  and standard deviation from mean of distribution of X is [tex]\sigma[/tex]

Using the above rule to find the needed percentage

Let the weight of organs be measured as values of random variable X

Then we have, [tex]X \sim N(\mu = 340, \sigma = 30)[/tex]

Thus,

a) For 99,7%, we have the interval of weights as [tex][\mu - 3\sigma, \mu + 3\sigma][/tex]

Evaluating, we get [tex][\mu - 3\sigma, \mu + 3\sigma] = [250, 430][/tex]

b) Since 280 is 340 - 60 which is 340 - twice of 30, and we 400 is 340 + 60 = 340 - twice of 30,

thus,

[tex]P(\mu - 2\sigma < X < \mu + 2\sigma) = 95\%\\\\P(280 < X < 400) = 95\%[/tex]

Thus, 95% organs weighs in between 280 grams and 400 grams.

c) We can use the complement of the event.

Thus, if we have [tex]P(280 < X < 400) = 95\%[/tex]

Then we have [tex]P(X < 280) + P(X > 400) = 100 - 95\% = 5\%[/tex]

d) Since we know that normal distribution is symmetric about its mean, thus,

[tex]P(X < \mu - k) = P(X > \mu + k)[/tex]

where k is a constant.

Putting k = 2 sigma, and using the fact that [tex]P(280 < X < 400) = 95\%[/tex]

[tex]P(X < 280) + P(X > 400) = 100 - 95\% = 5\%\\2P(X>400) = 5\%\\P(X > 400) = 2.5\%\\P(X\leq 400) = 100 - 2.5\% = 97.5\%[/tex]

Similarly putting k = 3, we get:

[tex]P(250 < X < 430) = 99.7\%\\P(X<250) + P(X>430) = 0.3\%\\2P(X<250) = 0.3\%\\P(X<250) = 0.15\%[/tex]

Thus,

probability that weights of organs is between 250 and 400 grams is

[tex]P(250 < X < 400) = P(X<400) - P(X < 250) = 97.5\% - 0.15\% = 97.35\%[/tex]

Thus, percentage of organs weighs between 250 grams and 400 ​grams is 97.35% approximately.

Thus,

The answers are

  • About 99.7​% of organs will be between 250 and 430
  • 95% organs weighs in between 280 grams and 400 grams
  • 5% percentage of organs weighs less than 280 grams or more than 400 ​grams
  • Percentage of organs weighs between 250 grams and 400 ​grams is 97.35% approximately.

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