Answer:
Horizontal component, [tex]d_x=178.69\ m[/tex]
Explanation:
It is given that,
Displacement of the submarine, d = 185 m
It is at an angle of 15 degrees below the horizontal. We need to find the horizontal component of the submarine's displacement. It is given by :
[tex]d_x=d\ cos\theta[/tex]
Substituting the values in above equation as :
[tex]d_x=185\times \ cos(15)[/tex]
[tex]d_x=178.69\ m[/tex]
So, the horizontal component of the submarine’s displacement is 178.69 meters. Hence, this is the required solution.
