Answer:
There is formed 3.6352 grams of oxygen
Explanation:
Step 1: The balanced equation
2N2O(g)⇔2N2(g)+O2(g)
Step 2: Calculate moles of dinitrogen monoxide
Moles = mass/ Molar mass
Moles of N2O = 10 grams of N2O / 44.01 g/mole
Moles of N2O = 0.227 moles
Step 3: Calculate moles of oxygen
When 2 moles of N2O is consumed, there is produced 1 mole of O2 ( and 2 moles of N2)
That means for 0.2272 moles of N2O consumed, there is produced 0.1136 moles of O2
Step 4: Calculate mass of O2
mass of O2 = moles of O2 * Molar mass of O2
mass of O2 = 0.1136 moles * 32 g/moles
mass of O2 = 3.6352 grams
There is formed 3.6352 grams of oxygen
