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Imagine an ideal (Carnot) refrigerator that keeps helium in its liquid state, at a temperature of about 4.00 K. The refrigerator, with the helium container inside, is in a laboratory where the temperature is about 294 K. Because of the imperfection of the insulation, 2.00 J of heat is absorbed by the refrigerator each hour. How much electrical energy E must be used by the refrigerator to maintain a temperature of 4.00 K inside for one hour?

Respuesta :

Answer:

147 Joule per hour

Explanation:

Cold temperature, T2 = 4 k

Hot temperature, T1 = 294 k

Heat absorbed, Q2 = 2 J per hour

Let the electrical energy is Q1.

by use of the condition of ideal refrigerator

[tex]\frac{Q_{1}}{Q_{2}}=\frac{T_{1}}{T_{2}}[/tex]

[tex]\frac{Q_{1}}{2}=\frac{294}{4}[/tex]

Q1 = 147 Joule per hour

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