Respuesta :
Answer: The equation for the dissociation and expression for the acid dissociation constant of benzoic acid is written below.
Explanation:
We are given an acid known as benzoic acid having chemical formula of [tex]C_6H_5COOH[/tex]
The chemical equation for the dissociation of acid into its acid when dissolved in water follows:
[tex]C_6H_5COOH(aq.)+H_2O(l)\rightleftharpoons C_6H_5COO^-(aq.)+H^+(aq.)[/tex]
The expression of acid dissociation constant for above equation follows:
[tex]K_a=\frac{[C_6H_5COO^-][H^+]}{[C_6H_5COOH]}[/tex]
The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression. So, the concentration of water is not taken in account in the expression.
Hence, the equation for the dissociation and expression for the acid dissociation constant of benzoic acid is written above.
A. The chemical equation for the dissociation of C₆H₅COOH is
C₆H₅COOH(aq) <=> H⁺(aq) + C₆H₅COO¯(aq)
B. The equilibrium constant Ka for the reaction is
Ka = [H⁺][C₆H₅COO¯] / [C₆H₅COOH]
A. How to write the dissociation equation
A dissociation equation is an equation showing the various ions present in a substance when dissolved in water.
The dissociation equation for C₆H₅COOH in water is given below:
C₆H₅COOH(aq) <=> H⁺(aq) + C₆H₅COO¯(aq)
B. How to obtain the equilibrium constant
The equilibrium constant for a given reaction is simply defined as the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.
The equilibrium constant for the reaction can be obtained as follow:
C₆H₅COOH(aq) <=> H⁺(aq) + C₆H₅COO¯(aq)
Ka = [H⁺][C₆H₅COO¯] / [C₆H₅COOH]
Learn more about equilibrium constant:
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