Answer:
566.3 m
Explanation:
The distance travelled by the object can be found by using the SUVAT equation:
[tex]d=ut+\frac{1}{2}at^2[/tex]
where
u is the initial velocity
t is the time
a is the acceleration
For the object in this problem:
u = 19 m/s
a = 2.5 m/s^2
Substituting t = 15 s, we find the distance travelled:
[tex]d=(19)(15)+\frac{1}{2}(2.5)(15)^2=566.3 m[/tex]
