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A plane drops a hamper of medical supplies from a height of 3250 m during a practice run over the ocean. The plane’s horizontal velocity was 129 m/s at the instant the hamper was dropped. What is the magnitude of the overall velocity of the hamper at the instant it strikes the surface of the ocean? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s.

Respuesta :

Answer:

Overall velocity will be 283.44355 m/sec

Explanation:

We have given height h = 3250 m

Horizontal velocity [tex]v_x=129m/sec[/tex]

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

As the hamper is dropped so initial velocity u = 0 m/sec

According to third equation of motion [tex]v^2=u^2+2gh[/tex]

[tex]v^2=0^2+2\times 9.8\times 3250[/tex]

[tex]v^2=63700[/tex][tex]v=252.388m/sec[/tex]

So vertical velocity [tex]v_y=252.388m/sec[/tex]

So overall velocity [tex]v=\sqrt{v_x^2+v_y^2}=\sqrt{129^2+252.388^2}=\sqrt{80340.70254}=283.4443553m/sec[/tex]

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