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Consider an investment that pays off $800 or $1,400 per $1,000 invested with equal probability.Suppose you have $1,000 but are willing to borrow to increase your expected return. What would happen to the expected value and standard deviation of the investment if you borrowed an additional $1,000 and invested a total of $2,000? What if you borrowed $2,000 to invest a total of $3,000? Assume that the borrowing rate is 0%.

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Answer:

Equal probability = 0.5

If you invest your own = $1,000

Expected value = 0.5(800) + 0.5(1,400)

                          = 400 + 700

                          = 1,100 or 10%

Standard deviation = 300

If you borrowed an additional $1,000 and invested a total of $2,000,

Expected value = 0.5(1,600-1,000) + 0.5(2,800-1,000)

                          = 300 + 900                          

                          = 1,200 or 20%

You have doubled the expected return.

[tex]SD=[0.5(600-1,200)^{2}+0.5(1,800-1,200)^{2}] ^{\frac{1}{2} }[/tex]

SD = 600

Therefore, standard deviation has doubled.

If you borrowed $2,000 to invest a total of $3,000, then,

Expected value = 0.5(2,400-2,000) + 0.5(4,200-2,000)

                          = 200 + 1,100                          

                          = 1,300 or 30%

You have tripled the expected return versus the unleveraged investment.

[tex]SD=[0.5(400-1,300)^{2}+0.5(2,200-1,300)^{2}] ^{\frac{1}{2} }[/tex]

SD = 900

Therefore, standard deviation has tripled versus the unleveraged investment.

The expected value and standard deviation would double in the case where an additional $ 1,000  is borrowed and it will triple where an additional $2,000 is borrowed.

What is an Expected value?

In Statistics and probability analysis, the expected value is calculated by multiplying each possible outcome with the probability that each outcome will appear and summarizing all those values.

In the given information, equal probability  is 0.5

Own investment is $1,000

[tex]\rm\,Expected\,value= 0.5(800) + 0.5(1,400)\\ \\ = 400 + 700\\ \\= 1,100\\\\Standard\,deviation = \sqrt{(800-1,100)^{2} \times 0.5 + (1,400-1,100)^{2}\times 0.5}\\\\= 300[/tex]

Case A: Borrowed an additional $1,000 and invested a total of $2,000

[tex]\rm\, Expected\,value = 0.5(1,600-1,000) + 0.5(2,800-1,000) \\ \\= 300 + 900 \\\\= 1,200\,or\,20\%\\\\\\Standard\,deviation = \sqrt{(600 - 1200)^{2} \times 0.5 + (1,800 - 1,200)^{2}\times 0.5}\\\\= 600[/tex]

The expected value and Standard deviation has doubled.

Case B: Borrowed $2,000 to invest a total of $3,000:

[tex]\rm\, Expected\,value = 0.5(2,400 -2,000) + 0.5(4,200-2,000) \\ \\\\= 200+ 1,100 \\\\= 1,300\,or\,30\%\\\\\\\\Standard\,deviation = \sqrt{(400 - 1300)^{2} \times 0.5 + (2,200 - 1,300)^{2}\times 0.5}\\\\= 900[/tex]

Hence, as we can see the value of expected value and standard deviation has tripled due to the additional amount of borrowing. It is proved that with every amount of increased borrowing the returns keep increasing.

To learn more about expected value, refer to the link:

https://brainly.com/question/17080700

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