Respuesta :
Answer:
[tex]q'=9.735\times 10^{-13}\ C/m^3[/tex]
Explanation:
Given that
219 m above the ground, the electric field is 141 N/C directed downward.
At 319 m above the ground, the electric field is 103 N/C downward.
If filed is going in to the region then it taken as negative and If filed is going out to the region then it taken as positive.
So net flux = 114 A - 103 A
Net flux= 11 A
Now from Gauss law
[tex]Net\ flux=\dfrac{q}{\varepsilon }[/tex]
[tex]\varepsilon =8.85\times 10^{-12}[/tex]
[tex]11\ A=\dfrac{q}{\varepsilon }[/tex]
q= 11 A ε
The average volume charge density(q') is the ratio of charge to the volume.
Volume = A .h
h= 319 - 219
h= 100 m
[tex]q'= \dfrac{11\ A\ \varepsilon }{ A\ h}[/tex]
[tex]q'= \dfrac{11\ \varepsilon }{h}[/tex]
[tex]q'= \dfrac{11\times 8.85\times 10^{-12}}{100}\ C/m^3[/tex]
[tex]q'=9.735\times 10^{-13}\ C/m^3[/tex]
So the charge per volume is [tex]q'=9.735\times 10^{-13}\ C/m^3[/tex]
