[tex]\boxed{t=0.57h}[/tex]
In this exercise, we know the following facts:
[tex]d=2.14mi \\ \\ v=3 \ 3/4 \ mph=3.75mph \\ \\ \\ Where: \\ \\ d: \ Distance \ from \ Alex's \ house \ to \ his \ school \\ \\ v: Alex's \ speed[/tex]
From physics, we know that distance (d), time (t) and speed (v) are related as the following equation:
[tex]v=\frac{d}{t}[/tex]
Isolating t:
[tex]t=\frac{d}{v} \\ \\ t=\frac{2.14}{3.75} \\ \\ \boxed{t=0.57h}[/tex]
Alex would need a little more than half an hour to get the school from his house.
t = 36 minutes
This is just about distance - time equations.
We are told that;
distance; d = 2 ¼ miles = 2.25 miles
Speed; v = 3 ¾ mph = 3.75 mph
Formula for time is;
time; t = d/v
Thus;
t = 2.25/3.75
t = 0.6 h
Converting to minutes gives;
t = 0.6 × 60
t = 36 minutes
Read more at; brainly.com/question/5898883
