Respuesta :

[tex]\bf \begin{cases} x = 1\implies &x - 1 = 0\\ x = 3\implies &x - 3=0 \end{cases}\qquad \implies (x-1)(x-3) = \stackrel{y}{0} \\\\\\ \stackrel{F~O~I~L}{x^2-4x+3}=0\implies 3(x^2-4x+3)=0\implies 3x^2-12x+9=y[/tex]

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