An airplane is flying on a flight path that will take it directly over a radar tracking station. If the distance between the tracking station and the airplane is decreasing at a rate of 400 miles per hour when the distance between them is 10 miles, what is the speed of the plane if the plane is always 3 miles above the ground?

Respuesta :

Answer:

The speed of planes is 419.31 miles per hours

Explanation:

Given that

[tex]\dfrac{dS}{dt}=-400\ miles/hr[/tex]

S= 10 miles

And we have to find [tex]\dfrac{dx}{dt}[/tex].

From triangle ABC

[tex]AC^2=AB^2+BC^2[/tex]

[tex]S^2=x^2+3^2}[/tex]

by differentiating with respect to time t

[tex]2S\dfrac{dS}{dt}=2x\dfrac{dx}{dt}[/tex]

[tex]S\dfrac{dS}{dt}=x\dfrac{dx}{dt}[/tex]

Now when S=10 miles then

[tex]10^2=x^2+3^2}[/tex]

x= 9.53 miles

So

[tex]S\dfrac{dS}{dt}=x\dfrac{dx}{dt}[/tex]

[tex]10\times (-400)=9.53\times \dfrac{dx}{dt}[/tex]

[tex]\dfrac{dx}{dt}=-419.31\ miles/hr[/tex]

So the speed of planes is 419.31 miles per hours

Ver imagen Netta00
Q&A Education