Answer:
The binomial factor of the given equation is 3x-8
Solution:
We know that,
[tex]9=3\times3=3^{2}[/tex]
[tex]64=8\times8=8^{2}[/tex]
According to the formula, [tex]a^{2}b^{2} = (ab)^{2}[/tex]
we get, [tex]9x^{2}-64=3^{2}x^{2}-8^{2}=(3x)^{2}-8^{2}[/tex]
From the formula, [tex]a^{2}-b^{2} = (a+b) (a-b)[/tex]
Here in this step we can consider a as 3x and b as 8
On substituting the values we can simplify the above equation as, [tex]9x^{2}-64 = (3x+8) (3x-8)[/tex]
The factors [tex]9x^{2}-64[/tex] are [tex](3x+8) and (3x-8)[/tex]
So, the answer is (3x-8)
