Answer:
Explanation:
Given
Weight of slider=2.6 lb
radius(r)=6.1 in.
[tex]\omega (\dot{\theta })=4.2 rad/s[/tex]
[tex]\ddot{\theta }=3.6 rad/s^2[/tex]
[tex]\dot{r}=2.1[/tex]
From FBD we can say that
[tex]\sum F_r=ma_r=m\left ( \ddot{r}-r\dot{\theta }^2\right )[/tex]
[tex]-T=\frac{2.6}{32.2}\left ( 0-\frac{6.1}{12}\times 4.2^2\right )[/tex]
T=0.726 lb
[tex]\sum F_{\theta }=ma_\theta=m\left ( r\ddot{\theta }+2\dot{r}\dot{\theta }\right )[/tex]
[tex]N=\frac{2.61}{32.2}\left [ \frac{6.1}{12}\times \left ( -2\right )+2\left ( -\frac{2.1}{12} \right )4.2\right ][/tex]
N=-0.201 lb(contact on B side)
