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You are breeding two polyploid species of cabbage. You cross the two different species (parent 1 x parent 2) and obtain F1 hybrids. The following meiotic pairing was observed in the F1 hybrid: F1 hybrid = 9 bivalents + 9 univalents a) How many chromosomes are there in a non-dividing somatic cell of an F1 plant (i.e. what is the organisms ploidy)? b) How many chromosomes are there in a non-dividing somatic cell of each parent (i.e. what is the organisms ploidy)?

Respuesta :

Answer:

1) 36 chromosomes

2) Parent 1 = 24 chromosomes

   Non dividing somatic cells = 12 chromosomes

Explanation:

Given data:

F1 hybrid = 9 bivalents + 9 univalents

A. The plant that does not divide F1 has 12 univalents + 12 bivalents. It has 36 chromosomes in total.

Note: 1 bivalent chromosomes consist of 2 chromosomes

B. That parent's non-dividing somatic cell comprises 12 chromosomes, while the number is 24 for parent 1.

Parent 1 = 24 chromosomes

Non dividing somatic cells = 12 chromosomes

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