Respuesta :
Answer:
The point-slope form of the line that passes through the origin and is parallel to a line with a slope of 2 is y = 2x
Solution:
The point slope form of the line that passes through the points[tex]\left(x_{1} y_{1}\right)[/tex] and parallel to the line with slope “m” is given as
[tex]\bold{y - y_{1} = m\left(x - x_{1}\right)}[/tex] --- eqn 1
where “m” is the slope of the line and [tex]\left(x_{1} y_{1}\right)[/tex] are the points that passes through the line.
From question, given that slope = 2
Given that the line passes through the origin. i.e. [tex]\left(x_{1} y_{1}\right) = (0,0)[/tex]
By substituting the values in eqn 1, the point slope form of the given line can be found out by,
y – 0 = 2(x-0)
y = 2x
Hence the point-slope form of the line that passes through the origin and is parallel to a line with a slope of 2 is y = 2x
