1. A normal distribution of scores has a standard deviation of 10. Find the z-scores corresponding to each of the following values: a) A score that is 20 points above the mean. b) A score that is 10 points below the mean. c) A score that is 15 points above the mean d) A score that is 30 points below the mean. 2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of 35 and a standard deviation of 6. Assuming these raw scores form a normal distribution:

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Answer with Step-by-step explanation:

The Z score in a distribution is found as

[tex]Z=\frac{X-\overline{X}}{\sigma }[/tex]

where

X is the given value

[tex]\overline{X}[/tex] is the mean of the observations

[tex]\sigma [/tex] is the standard deviation of the data

The values of oach part is found as under:

Part a)

Since it is given that score is 20 points over mean thus we can write

[tex]X=20+\overline{X}\\\\X-\overline{X}=20[/tex]

Using the above relation we get

[tex]Z_a=\frac{20}{10}=2[/tex]

Part b)

Since it is given that score is 10 points below mean thus we can write

[tex]X=\overline{X}-10\\\\X-\overline{X}=-10[/tex]

Using the above relation we get

[tex]Z_b=\frac{-10}{10}=-1[/tex]

Part c)

Since it is given that score is 15 points over mean thus we can write

[tex]X=15+\overline{X}\\\\X-\overline{X}=15[/tex]

Using the above relation we get

[tex]Z_c=\frac{15}{10}=1.5[/tex]

Part d)

Since it is given that score is 30 points below mean thus we can write

[tex]X=\overline{X}-30\\\\X-\overline{X}=-30[/tex]

Using the above relation we get

[tex]Z_d=\frac{-30}{10}=-3[/tex]

Using the normal distribution, the corresponding z-scores are:

a) z = 2.

b) z = -1.

c) z = 1.5.

d) z = -3.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • It measures how many standard deviations the measure is from the mean.  

In this problem, we have a standard deviation of [tex]\sigma = 10[/tex].

Item a:

  • Score 20 points above the mean, thus [tex]X = \mu + 20[/tex]

The z-score is:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{\mu + 20 - \mu}{10}[/tex]

[tex]Z = 2[/tex]

Item b:

  • Score 10 points below the mean, thus [tex]X = \mu - 10[/tex]

The z-score is:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{\mu - 10 - \mu}{10}[/tex]

[tex]Z = -1[/tex]

Item c:

  • Score 15 points above the mean, thus [tex]X = \mu + 15[/tex]

The z-score is:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{\mu + 15 - \mu}{10}[/tex]

[tex]Z = 1.5[/tex]

Item d:

  • Score 30 points below the mean, thus [tex]X = \mu - 30[/tex]

The z-score is:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{\mu - 30 - \mu}{10}[/tex]

[tex]Z = -3[/tex]

A similar problem is given at https://brainly.com/question/16645591

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