Answer:
a)(A) static friction
b)[tex]\mu _s=0.085[/tex]
Explanation:
Given that
r = 30.8 cm
V = 50.8 cm/s
a)
(A) static friction
b)
At the condition of motion
Static friction = Centrifugal force
[tex]\mu _s\ m\ g=\dfrac{mV^2}{r}[/tex]
[tex]\mu _s\ g=\dfrac{V^2}{r}[/tex]
[tex]\mu _s\times 980=\dfrac{50.8^2}{30.8}[/tex]
[tex]\mu _s=0.085[/tex]
In this exercise we have to use the knowledge of centripetal force to describe the types of forces identified in the exercise, thus we have:
A)Static frition
B) [tex]\mu_s=0.085[/tex]
organizing the information given by the utterance we find that:
Centripetal force is the resultant force that acts on a body and describes a motion in a circular path. It is responsible for changing the direction of the body's velocity and, in addition, it always points to the center of the curves, so that the angle formed between this force and the velocity vector is always 90º.
A) We are dealing with a centripetal force that way we know that it is a force that acts on a body that is in motion that needs to keep rotating. The only traction used is the static friction.
B)knopwing that the formula, we have:
[tex]\mu_s*m*g=(mV^2)/r\\\mu_s*g=V^2/r\\\mu_s(980)=(50.8)^2/(30.8)\\\mu_s=0.085[/tex]
See more about centripetal force at brainly.com/question/10596517
