Compound 1 has a composition of 46.7 mass % of element A and 53.3 mass % of element B. A and B also form a second binary compound (compound 2). If the compositions of the two compounds are consistent with the law of multiple proportions, which of the following compositions could be that of compound 2? A. 23.4 mass % A 76.6 mass % B B. 30.4 mass % A 69.6 mass % B C. 33.3 mass % A 66.7 mass % B D. 53.3 mass % A 46.7 mass % B E. 73.3 mass % A 26.7 mass % B

Respuesta :

Answer:

The answer to your question is: B.

Explanation:

Law of multiple proportions: this law states that when 2 elements combine to form more than 1 compound the weights that one element that combines with a fixed weight and the other are with a ratio of small whole numbers.

Then, the proportion of B:A in compound 1 is:

                                                                           53.3/ 46.7 = 1.14

Options                                                         Ratio       Compare ratio

                                                                                     with compound 1

A. 23.4 mass % A 76.6 mass % B               3.27                2.87

B. 30.4 mass % A 69.6 mass % B               2.29               2

C. 33.3 mass % A 66.7 mass % B               2.0                  1.75

D. 53.3 mass % A 46.7 mass % B               0.88                0.77

E. 73.3 mass % A 26.7 mass % B               0.36                0.31

The answer is B because there is a proportion between this compond and compound 1.

The study of chemicals and bonds is called chemistry. There are different types of elements and are metals and nonmetals.

The correct answer is option B which is 30.4%.

What is a binary compound?

  • A binary compound is something consisting of precisely two elements.
  • An element is a type of substance that can't be further divided into simpler substances through chemical methods.

Law of multiple proportions

  • This law states that when 2 elements combine to form more than 1 compound the weights that one element that combines with a fixed weight and the other are with a ratio of small whole numbers.

Then, the proportion of B: A in compound 1 is: [tex]\frac{53.3}{46.7} = 1.14[/tex]

Options                                                         Ratio       Compare ratio

                                                                                    with compound 1

A. 23.4 mass % A 76.6 mass % B              3.27                2.87

B. 30.4 mass % A 69.6 mass % B               2.29               2

C. 33.3 mass % A 66.7 mass % B               2.0                  1.75

D. 53.3 mass % A 46.7 mass % B               0.88                0.77

E. 73.3 mass % A 26.7 mass % B              0.36                0.31

The answer is B because there is a proportion between this compound and compound 1.

For more information about the binary compound, refer to the link:-

https://brainly.com/question/7932885

Q&A Education