In a rigid transformation, the Euclidean distance between every two points on the preimage and image is the same
The correct option for the type of transformation that maps ΔQRS to ΔQ'R'S' is: Rotation
The reason the selected option is correct is as follows:
Question: Please find attached a diagram from a similar question showing ΔQRS and ΔQ'R'S'
From the attached diagram it can be seen that the length of the sides;
RS = R'S'
SQ = S'Q'
RQ = R'Q'
From the diagrams, it can also be seen that in ΔQRS and ΔQ'R'S'
∠Q = ∠Q'
∠R = ∠R'
∠S = ∠S'
Therefore, ΔQRS is congruent (have the same dimensions) to ΔQ'R'S' and the relative position of the sides and angles in ΔQRS and ΔQ'R'S' are equal, the difference is that ΔQ'R'S' is the rotated image of ΔQRS
Therefore, the type of transformation is a rotation transformation
Learn more about rigid transformations here:
https://brainly.com/question/15577335
