Answer:
-13.3 m, -40.8 m
Explanation:
We can find the components of the vector by using the equations:
[tex]v_x = v cos \theta[/tex]
[tex]v_y = v sin \theta[/tex]
where
v is the magnitude of the vector
[tex]\theta[/tex] is the angle representing the direction of the vector (measured above the positive x-direction)
For the vector in this problem,
v = 42.9 m
[tex]\theta=252^{\circ}[/tex]
Therefore its components are
[tex]v_x = (42.9) ( cos 252^{\circ})=-13.3 m\\v_y = (42.9)( sin 252^{\circ})=-40.8 m[/tex]
