What is the average acceleration of the object represented in the graph above over the 10 seconds? I know the answer isn’t C

Question

contestada

Respuesta :

AL2006 AL2006 · Answer 1 · 2019-10-04T22:16:59+02:00

It's always a good idea to start with the definition of the thing you're trying to find.

This problem is just trying to find out whether you KNOW the definition of acceleration. You may know it, but you haven't used it yet.

Average acceleration = (change in velocity) divided by (total time).

Change in velocity = (end value) minus (start value)

Change in velocity = (20m/s) - 0

Change in velocity = 20 m/s

Time = 10 s

Average acceleration = (20m/s)/(10s)

Average acceleration = 2 m/s^2

Abdulazeez10 Abdulazeez10 · Answer 2 · 2021-11-04T16:38:14+01:00

The average acceleration of the object represented in the graph over the 10 seconds is 2 m/s²

From the question,

We are to determine the average acceleration of the object represented in the graph

Average acceleration is the rate at which the velocity changes.

Average acceleration can be calculated using the formula

[tex]Average\ acceleration = \frac{Change\ in\ velocity}{Change\ in\ time}[/tex]

[tex]Average\ acceleration=\frac{v_{f}-v_{0} }{t_{f}-t_{0} }[/tex]

Where [tex]v_{f}[/tex] is the final velocity

[tex]v_{0}[/tex] is the initial velocity

[tex]t_{f}[/tex] is the final time

and [tex]t_{0}[/tex] is the initial time

From the graph

[tex]v_{f} = 20 \ m/s[/tex]

[tex]v_{0} = 0 \ m/s[/tex]

[tex]t_{f}= 10 \ secs[/tex]

[tex]t_{0}= 0 \ secs[/tex]

Putting the parameters into the formula, we get

[tex]Average\ acceleration = \frac{20-0}{10-0}[/tex]

[tex]Average\ acceleration = \frac{20}{10}[/tex]

[tex]Average\ acceleration = 2 \ m/s^{2}[/tex]

Hence, the average acceleration of the object represented in the graph over the 10 seconds is 2 m/s²

Learn more here: https://brainly.com/question/17587670