Answer:
a) 0.4567
b) 6 hours
Step-by-step explanation:
We are given the following information the question:
The battery life follows a normal distribution with
[tex]\mu = 9.75\\\sigma = 2.3[/tex]
Formula:
[tex]z = \displaystyle\frac{x-\mu}{\sigma}[/tex]
a) We have to find probability such that battery life exceeds 10 hours, that is,
P(X>10)
[tex]P(z > \displaystyle\frac{10 - 9.75}{2.3}) = P(z>0.1086)\\\\= 1 - P(z \leq 0.1086)\\= 1- 0.5433\\=0.4567[/tex]
b) We have to find battery life such that
[tex]P(X \leq x) = 0.05\\\\P(z \leq \displaystyle\frac{x-9.75}{2.3}) = 0.05\\\\\displaystyle\frac{x-9.75}{2.3} = -1.64 \\\\x = (-1.64)(2.3) + 9.75\\x = 5.978[/tex]
Here, we calculated the value of z from the normal distribution table.
So, after approximately 6 hours one should plan to recharge the phone.