Answer:
The difference is D. 90 min
Step-by-step explanation:
The distance that Linda covers (DL) in terms of time in hours (t) is:
[tex]DL=2mph*t[/tex]
and the distance that Tom covers (DT) in terms of time in hours (t) is:
[tex]DT=6mph*(t-1)[/tex]
We need to subtract 1 hour from Tom's time because he started walking an hour later than Linda.
When Tom has covered the same distance that Linda has, DT=DL, so:
[tex]2mph*t=6mph(t-1)[/tex]
solving for t, we will find the time Tom needs to cover the same distance as Linda:
[tex]2t=6t-6[/tex]
[tex]2t-6t=-6[/tex]
[tex]t=\frac{6}{4}=1.5h[/tex]
Now, when Tom has covered twice the distance than Linda, DT=2DL, so:
[tex]6mph(t-1)=2*2mph*t[/tex]
Again, solving for t:
[tex]6t-6=4t[/tex]
[tex]6t-4t=6[/tex]
[tex]t=\frac{6}{2}=3h[/tex]
So, the difference between those two times is:
[tex]3h-1.5h=1.5h=90min[/tex]