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Line GH contains points G(–2, 6) and H(5, –3). What is the slope of ?

–negative StartFraction 7 Over 3 EndFraction
–negative StartFraction 9 Over 7 EndFraction
–negative StartFraction 7 Over 9 EndFraction
–negative StartFraction 3 Over 7 EndFraction

Respuesta :

CharlieBrown2002

Answer:

[tex]\Huge\boxed{\mathsf{-\frac{9}{7} }}}[/tex]

Step-by-step explanation:

SLOPE FORMULA:

[tex]\displaystyle \mathsf{\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}  }[/tex]

Y2=(-3)

Y1=6

X2=5

X1=(-2)

Solve.

[tex]\displaystyle \mathsf{\frac{(-3)-6}{5-(-2)}=\frac{(-3)-6}{5+2}= \frac{-9}{7}=\boxed{\mathsf{-\frac{9}{7}}  }}[/tex]

The slope is -9/7.

yasypichu

Answer:

The answer is B

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