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The vertices of the pentagon ABCDE are A(0,4), B(4,0), C(3,- 4), D(-3,- 4), E(-4,0). If the pentagon is translated 5 units down and 4
units right, the new vertices are:

a. A'(4, -1), B'(8,-5), C'(7,-9), D'(1,-9), E'(0,-5)
b. A'(4, -1), B'(8,-5), C'(7,-9), D'(1,-9), E'(1,-5)
C. A'(4, -1), B'(5,-5), C'(7,-9), D'(1,-9), E'(0,-5)
d. A'(4, -1), B'(8,-5), C'(7.-9), D'(0,-9), E'(0,-5)​

The vertices of the pentagon ABCDE are A04 B40 C3 4 D3 4 E40 If the pentagon is translated 5 units down and 4units right the new vertices area A4 1 B85 C79 D19 class=

Respuesta :

joseaaronlara

Answer:

The answer to your question is: a. A'(4, -1), B'(8,-5), C'(7,-9), D'(1,-9), E'(0,-5)

Step-by-step explanation:

pentagon ABCDE

Translated 5 units down and 4 units right

                               Changes                                    Final Vertices

A (0 , 4)                   A (0 + 4 , 4 - 5)                           A (4, -1)

B (4 , 0)                   B (4 + 4, 0 - 5)                            B (8, -5)

C (3 , - 4)                 C (3 + 4, - 4 - 5)                          C (7, -9)

D (-3 , - 4)                D (-3 + 4, - 4- 5)                         D (1, -9)

E (-4 , 0)                   E (-4 + 4, 0 - 5)                          E (0, -5)

abnerjoseperez

A) A(4,-1)B (8,-5)C (7,-9) D(1,-9) E(0, -5)

Step-by-step explanation:

To every coordinate pair, you sum 4 to each X value (since it is moving right) and substract 5 to the Y values, (because they are moving down)

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