Answer:
402m
Explanation:
We can solve this easily by using the free fall formula:
[tex]v_f^2=v_0^2+2ad[/tex]
On both cases the final velocity will be 0m/s (maximum height), so we have:
[tex]v_0^2=-2ad[/tex]
We know that the velocity the person imparts to the ball will be the same either on Earth or on the Moon, so we write for both cases:
[tex]v_0^2=-2a_Ed_E[/tex]
[tex]v_0^2=-2a_Md_M[/tex]
Which means
[tex]2a_Ed_E=2a_Md_M[/tex]
So we get (taking into account that gravity on earth is 6 times gravity on the Moon):
[tex]d_M=\frac{a_Ed_E}{a_M}=\frac{6a_Md_E}{a_M}=6d_E=6(67m)=402m[/tex]
