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A piece of gold jewelry weighs 11.54 g and has a volume of 0.675 cm3. The jewelry contains only gold (density = 19.3 g/cm3) and silver (density = 10.5 g/cm3). Assuming that the total volume of the jewelry is the sum of the volumes of the gold and silver that it contains, calculate the percentage of gold in the jewelry.

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luchoprat

Answer:

Percentage of gold = 84.6%

Explanation:

Suppose the jewelry has x g of gold and y g of silver

The mass of both is the total mass of the jewelry then:

x + y = 11.54

And as the problem says the total volume is the sum of both volumes.

volume = mass / density

[tex]\frac{x}{19.3} + \frac{y}{10.5} = 0.675[/tex]

Solving the system you get:

x = 9.764 g

y = 1.776 g

The percentage of gold in the jewelry is:

[tex]X_{gold} = \frac{9.764}{11.54} * 100 = 84.6\%[/tex]

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