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Suppose you are an astronaut and you have been stationed on a distant planet. You would like to find the acceleration due to the gravitational force on this planet so you devise an experiment. You throw a rock up in the air with an initial velocity of 11 m/s and use a stopwatch to record the time it takes to hit the ground. If it takes 5.4 s for the rock to return to the same location from which it was released, what is the acceleration due to gravity on the planet?

Respuesta :

Answer:[tex]4.07 m/s^2[/tex]

Explanation:

Given

time taken= 5.4 s

Velocity=11 m/s

let t be the time taken in earth

therefore

[tex]t=\frac{2v}{g}=\frac{2\times 11}{9.8}=2.24 s[/tex]---1

In distant planet

[tex]t'=\frac{2v}{g'}[/tex]

[tex]g'=\frac{2v}{t'}=\frac{2\times 11}{5.4}=4.07 m/s^2[/tex]

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