[tex]\mathrm{Ca}+\mathrm{ZnCO}_3\Rightarrow\mathrm{CaCO}_3+\mathrm{Zn}[/tex]
Zn and ZnCO_3 occur in a 1:1 ratio in this reaction. Zn has a molar mass of about 65.38 g/mol; C has a molar mass of 12.011 g/mol; and O has a molar mass of 15.999 g/mol. So ZnCO_3 has a total molar mass of about 125.4 g/mol. In this reaction,
[tex](162\,\mathrm g\text{ ZnCO}_3)\left(\dfrac1{125.4}\dfrac{\rm mol}{\rm g}\right)=1.29\,\mathrm{mol}\text{ ZnCO}_3[/tex]
are involved, so that about 1.29 moles of Zn are produced, which has a mass of
[tex]1.29\,\mathrm{mol}\text{ Zn}\left(65.38\dfrac{\rm g}{\rm mol}\right)=84.3\,\mathrm g\text{ Zn}[/tex]
(round up to 88 g)
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Masses add, so the total mass of the solution is 50.5 g
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Hard to answer without the image...
1. mass of Zn = 74 g
2. mass of solution = 0.5 + 50.0 = 50.5 g
3 mass of reactant = mass of the products
1.
calcium + zinc carbonate → calcium carbonate + zinc
Ca + ZnCO₃ → CaCO₃ + Zn
calcium = 64 grams
zinc carbonate = 162 grams
calcium carbonate = 152 grams
let the mass of zinc = x grams
Using the law of conservation of matter that states that matter is neither created nor destroyed. This law is known as law of indestructibility of matter. It simply implies the total mass of product is the same as the total mass of the reactant. Therefore,
64g + 162g = 152g + x
226 - 152 = x
x = 74g
mass of Zn = 74 g
2.
He dissolves 0.5 gram of sugar in a beaker containing 50.0 g of water. The mass of the solution can be calculated as follows:
mass of solution = 0.5 + 50.0 = 50.5 g
3.
Using the law of conservation of mass, the mass of the reactant should be equals to the mass of the products.
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