Answer:
The acceleration due to gravity is -2.23m/s^2
Explanation:
Here we have a parabolic motion, the motion on X is defined as a constant velocity motion, so we can obtain the time by:
[tex]t=\frac{d}{v}\\t=\frac{8m}{6.55m/s}=1.22s[/tex]
Now on the Y axis we experiment a contant acceleration motion:
[tex]x=x0+vo*t+\frac{1}{2}*a*t^2\\where:\\x=0\\vo=0\\[/tex]
so:
[tex]a=\frac{(-1.40m)(2)}{(1.22s)^2}=-2.23m/s^2[/tex]
Answer:
[tex]g = 1.88 m/s^2[/tex]
Explanation:
As we know that the rock is projected at speed
v = 6.55 m/s
the horizontal distance traveled by the rock is given as
d = 8 m
time taken by the rock to move this distance is given as
[tex]t = \frac{d}{v}[/tex]
[tex]t = \frac{8}{6.55}[/tex]
[tex]t = 1.22 s[/tex]
now in the same time it will drop to the ground
so we have
[tex]y = \frac{1}{2}gt^2[/tex]
[tex]1.40 = \frac{1}{2}g(1.22^2)[/tex]
[tex]g = 1.88 m/s^2[/tex]
