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A cart rolling down an incline that is 60 meters long. If the cart has a beginning speed of 2.0 m/s and it
speeds up to 22 m/s. What was the cart's acceleration?

Respuesta :

MathPhys

Answer:

4 m/s²

Explanation:

Given:

Δx = 60 m

v₀ = 2.0 m/s

v = 22 m/s

Find: a

v² = v₀² + 2aΔx

(22 m/s)² = (2.0 m/s)² + 2a (60 m)

a = 4 m/s²

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