Respuesta :

santiquirogal

Answer:

0.14 kg

Explanation:

a= (Vf²- Vi²)/2.d

the final velocity is 0 (rest), and the initial velocity is 92 mi/h, that is equal to 41 m/s and the distance is 0.15 meters.

a= -5603 m/s² the minos means that the object is decelerating.

then we can use the second Newton law

F= m.a

m= F/a -----> m= 803N / 5603 m/s²

m= 0.14 kg

ayfat23

Mass of the ball is [tex]0.14kg[/tex]

  • Mass of an object can be regarded as the term that measure of how much of  matter that is present  in an object,
  • using the two equations of motion,
  • [tex]v^{2} = x^{2} + 2as[/tex]  ..........(1)
  • [tex]F= ma[/tex].....(2)

where

v= final velocity of the catcher = 0

u=initial velocity of the catcher= [tex]92mi/h[/tex]

but[tex]1 \frac{mil}{h } =0.447 \frac{m } { s }[/tex]

Then[tex]u=( 92*0.447) = 41m/s[/tex]

  • F= force exerted
  • a= acceleration
  • m= mass of the ball = ??
  • s= distance covered =[tex]0.15m[/tex]

Then substitute the values,

  • [tex]v^{2} = u^{2} + 2as[/tex]
  • 0= [tex](41)^{2} + (2*0.15 * a)[/tex]
  • [tex]0= 1681+ 0.3a[/tex][tex]a= - ( \frac{1681}{0.3} )[/tex]

[tex]=-5603 m/s^2[/tex]

Then from second equation we can substitute

  • [tex]F= ma[/tex]
  • [tex]mass= \frac{F }{ a }[/tex]
  • =[tex]\frac{803}{5603}[/tex]
  • [tex]m= 0.14kg[/tex]

Therefore, the mass of the ball is [tex]m= 0.14kg[/tex]

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