Respuesta :
Answer: 0.2 Â hours
Explanation: In order to solve this question we have to considerer that a recargeable battery can supply 1800 mA  in one hour then we have to determine how long could this battery drive current through a long, thin wire of resistance 34 Ω .
Besides, this battery has a voltage of 12 V
so by using the Ohm law we also know that V=R*I,
Fron this we can obtain:
I= V/R= 12 V/ 34 Ω=0.35 A= 350 mA
then considering that this battery can supply 1800 mA in one hour we have this battery can supply 350 mA Â in x time in the form:
1hour------- 1800 mA
x hour--------350 mA
time= 350/1800= 0.2 hour
The current flowing through the wire depends on the voltage across the wire and its resistance.
The current flowing through the wire is for 0.019 hrs.
What is current?
Current is the flow of electrical charge carriers that is defined as the number of electrical charge moving per second.
Part A
Given that voltage across the battery is 1.2 V and the resistance of the thin wire is 34 ohms.
The current flowing through the wire per second is given as,
[tex]I = \dfrac {V}{R}[/tex]
[tex]I = \dfrac {1.2}{34}[/tex]
[tex]I = 0.03529\;\rm A[/tex]
[tex]I = 35.29 \;\rm mA[/tex]
Given that the total current flowing through the wire in one hour is 1800 mA. Then 35.29 mA current flowing through the wire in the time given as,
[tex]1800\;\rm mA = 1\;hr[/tex]
[tex]\Delta t = \dfrac {1}{1800\;\rm m}\times 35.29\;\rm m[/tex]
[tex]\Delta t = 0.019\;\rm hr[/tex]
Hence we can conclude that the current flowing through the wire for 0.019 hrs.
To know more about the current, follow the link given below.
https://brainly.com/question/2285102.
