Respuesta :
Answer:
(a) Current i =0.7280 A
(b) Energy = 238993.922 j
(c) Height h = 325.161 m
Explanation:
We have given that voltage V = 11.4 Volt
Power P = 8.3 Watt
Time t = 8 hour
We know that 1 hour = 3600 sec
So 8 hour = 28800 sec
(a) We have to calculate current
We know that power = voltage ×current
Current [tex]i=\frac{P}{V}=\frac{8.3}{11.4}=0.7280A[/tex]
(b) We have to calculate the energy
Resistance is given by [tex]R=\frac{V}{i}=\frac{11.4}{0.7280}=15.657ohm[/tex]
We know that energy [tex]E=i^2Rt=0.7280^2\times 15.657\times 28800=238993.922j[/tex]
(a) Energy required to lift the mass is given by mgh
So [tex]mgh=238993.922j[/tex]
We have given mass m = 75 kg
So [tex]75\times 9.8\times h=238993.922j[/tex]
h=325.161 m
a)The rate of flowing of charge is said to be the electric current. The current delivered will be is 0.7280 A
(b)The battery capable of supplying 238993.922 j amount of energy.
(c)He can raise the height up to 325.161 m using the energy of the battery.
What is electric current?
The rate of flow of charge is said to be the electric current. A charge is responsible for the flow of electric current. Its unit is ampere and calculated by the ammeter.
voltage(V) = 11.4 volts.
Power(p)= 8.3 watts
Time (t)= 8 hours
mass (m)= 75 kg
We know that
one hour equals 3600 seconds.
As a result, 8 hours equals 28800 seconds.
(a)
Power is equal to the product of voltage and current.
[tex]\rm{P = VI}[/tex]
[tex]I = \frac{P}{V}[/tex]
[tex]I = \frac{8.3}{11.4}[/tex]
[tex]\RM{I = 0.7280 A}[/tex]
Hence the current delivered will be is 0.7280 A.
(b)
According to ohm's law
[tex]\rm V = IR[/tex]
[tex]\rm{R=\frac{V}{I} }[/tex]
[tex]\rm{R=\frac{11.4}{0.7280} }[/tex]
[tex]\rm{R=15.6 ohm }[/tex]
The formula for the heat generated by supplied
[tex]\rm{H = I^{2} RT}[/tex]
[tex]\rm{H = 0.7280^{2}\times 15.6\times28800}[/tex]
[tex]\rm{H = 238993.922 J}[/tex]
Hence the battery is capable of supplying 238993.922 j amount of energy
(c)
The potential energy required to lift the body is given by
[tex]\rm{ PE = mgh}[/tex]
This potential energy is get converted into the amount of energy supplied.
[tex]\rm{ PE = mgh= 238993.922 J}[/tex]
[tex]\rm{h = \frac{PE}{ mg} }[/tex]
[tex]\rm{h = \frac{238993.922}{ 75\times9.81} }[/tex]
[tex]\rm{h = 325.161 m }[/tex]
Hence he can raise the height up to 325.161 m using the energy of the battery.
To learn more about the electric current refer to the link;
https://brainly.com/question/7643273
