Answer:
Explanation:
Given
length of run=190 m
maximum speed[tex]=305 m/min\approx 5.08 m/s[/tex]
[tex]a=1.22 m/s^2[/tex]
time require to reach max speed
v=u+at
[tex]5.08=0+1.22\times t[/tex]
[tex]t=\frac{5.08}{1.22}=4.16 s[/tex]
distance traveled in t=4.16 s
[tex]s=ut+\frac{at^2}{2}[/tex]
[tex]s=0+\frac{1.22\times 4.16^2}{2}=10.55 m[/tex]
Now time taken to stop from max speed to zero
v=u+at
[tex]0=5.08-1.22\times t[/tex]
t=4.16 s
so the distance travel by car during the deceleration is 10.55 m
total time time taken=4.16+4.16=8.32 s
