Answer:[tex]1.88 m/s^2[/tex]
Explanation:
Given
initial horizontal speed of =6.55 m/s
height of rock=1.4 m
Horizontal distance=8 m
Time to travel 8 m
[tex]8=6.55\times t[/tex]
[tex]t=\frac{8}{6.55}=1.22 s[/tex]
Time to cover 1.4 m
[tex]h=\frac{at^2}{2}[/tex]
[tex]1.4=\frac{g'1.22^2}{2}[/tex]
[tex]g'=1.88 m/s^2[/tex]