Answer:
[tex]\large \boxed{\text{178 g}}[/tex]
Explanation:
The density of ethanol is 0.789 g/cm³
.
[tex]\begin{array}{rcl}D& = & \dfrac{m}{V}\\\\0.789 & = & \dfrac{m}{225}\\\\m & = & 0.789 \times 225\\& = & \textbf{178 g}\\\end{array}\\\text{The mass is $\large \boxed{\textbf{178 g}}$}[/tex]
