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An eagle is flying horizontally at a speed of 2.60 m/s when the fish in her talons wiggles loose and falls into the lake 4.60 m below. Calculate the velocity (in m/s) of the fish relative to the water when it hits the water. (Assume that the eagle is flying in the +x-direction and that the +y-direction is up.)

Respuesta :

Answer:

9.495 m/s

Explanation:

initial horizontal speed, ux = 2.60 m/s

initial vertical speed, uy = 0

height, h = 4.60 m

acceleration due to gravity, g = 9.8 m/s^2

Let the speed of fish is v as it hits the water level.

Use third equation of motion in vertical direction

[tex]v^{2}= u^{2}+2as[/tex]

[tex]v^{2}= 0^{2}+2\times 9.8\times 4.60[/tex]

v = 9.495 m/s

Thus, the fish hits the water level with the speed of 9.495 m/s.

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