Answer:
Explanation:
Given
acceleration in x direction
[tex]a_x=5.10 m/s^2[/tex]
Final velocity in x direction [tex]v_x=3500 m/s[/tex]
time taken=150 s
let initial velocity in x direction be [tex]u_x[/tex]
[tex]v_x=u_x+a_x\times t[/tex]
[tex]3500-5.10\times 150=u_x[/tex]
[tex]u_x=2735 m/s[/tex]
Now solve for Y direction
[tex]v_y=u_y+a_y\times t[/tex]
[tex]4046=u_y+7.3\times 150[/tex]
[tex]u_y=4046-1095=2951 m/s[/tex]
[tex]tan\theta =\frac{u_y}{u-x}=\frac{2951}{2735}[/tex]
[tex]tan\theta =1.078[/tex]
[tex]\theta =47.14 ^{\circ}[/tex] ACW from x-axis