Answer:
600 kCal/ day
Explanation:
You can solve this type of problems using proportions, with the rule of three.
Follow these steps:
1. Analyze the giving data
2. Organize it
3.Write the proportions
4. Clear the value you are looking for
5. Solve the equations by multiplying or dividing
Now for the exercise:
You have the following data:
3000 mL Solution per 1 day ----> 3000 mL S
The concentration of the solution is
5 g of dextrose per 100 mL Solution ----> 5g D - 100 mL S
The glucose provides some specific energy
4 kCal per 1 g of dextrose ----> 4kCal - 1 g D
First find the total grams of dextrose (glucose) given in one day.
3000 mL S - x g D?
100 mL S - 5 g D
The grams of glucose given in one day
xg D? = 3000 mL S(5 g D)/100 mL S
you also can cancel the units mL S
xg D? = 150 g D.
Answer: The grams given in one day of glucose are 150 g
/day
Now find the total Energy in those grams:
4 kCal - 1 g D
x kCal?-150 g D
Clear x kCal?
x kCal? = 4kCal (150g D)/(1g D)
x kCal? = 600 kCal remember is for one day!
so the answer is
The patient is receiving 600 kCal/day
