Answer:
Net force that acts on the pilot = 93 N (rounded off to nearest 1 N)
Explanation:
An airplane has a mass of 3.1 × [tex]10^{4}[/tex] Kg
The applied force for it to take off = 3.7 × [tex]10^{4}[/tex] N
According to Newton's second law of motion; applied force (F) is directly proportional to the product of mass (M) and acceleration (A) of the object.
i.e F ∝ MA
This means that the applied force (F) is also directly proportional to the mass (M) of the object.
i.e F ∝ M
Acceleration (A) in this case is constant.
If the airplane's mass = 3.1 × [tex]10^{4}[/tex] kg requires 3.7 × [tex]10^{4}[/tex] N to take off,
Then the pilot's mass of 78 kg will require;
[tex]\frac{78 * 3.7 * 10^4}{3.1 * 10^4}[/tex] = 93.09677419 N = 93N (rounded off to nearest 1 N)
