Respuesta :
Answer:
The factor of [tex]9 x^{4}+12 x^{3}+21 x^{2} \text { is } 3 x^{2}\left(3 x^{2}+4 x+7\right)[/tex]
Solution:
From question given that the equation is
[tex]9 x^{4}+12 x^{3}+21 x^{2}[/tex]
We have to find the factors of the given equation.
By taking 3 as a common term in above expression,
[tex]=3\left(3 x^{4}+4 x^{3}+7 x^{2}\right)[/tex]
By taking “x” as a common term in above expression, we get equation as
[tex]=3 x\left(3 x^{3}+4 x^{2}+7 x\right)[/tex]
Again taking “x” as a common term in above expression, we get
[tex]=3 x^{2}\left(3 x^{2}+4 x+7\right)[/tex]
[tex]\left(3 x^{2}+4 x+7\right)[/tex] cannot be factorized.(imaginary roots)
Hence factor of [tex]9 x^{4}+12 x^{3}+21 x^{2} \text { is } 3 x^{2}\left(3 x^{2}+4 x+7\right)[/tex]
Answer:
3x2(3x2 + 4x + 7)
Step-by-step explanation:
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