Answer:
116.2 m
Explanation:
We can solve the problem by using the following SUVAT equation:
[tex]v^2-u^2=2ad[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
d is the stopping distance
In this problem:
v = 0 (the bus comes to a stop)
[tex]u=60 km/h \cdot \frac{1000}{3600}=16.7 m/s[/tex] is the initial velocity
[tex]a=-1.2 m/s^2[/tex] is the deceleration
d is the stopping distance
Solving for d,
[tex]d=\frac{v^2-u^2}{2a}=\frac{0-(16.7)^2}{2(-1.2)}=116.2 m[/tex]
