Respuesta :
Answer:
time is 35.53 min
Explanation:
given data
mass of water m = 2 L = 2kg
temperature = 20°C
diameter dP = 20 cm
rad
delivers = 10 kW/m²
to find out
Calculate the time
solution
we know here energy required to boil water that is
Q = mcΔT .........1
m is mass and ΔT is change in temperature and c is 4186 J/kg°C
so Q = 2 × 4186 × ( 100-20)
Q = 669760 J = 669.760 kJ
so power will be
power = [tex]{deliver}*{area}[/tex]
power = [tex]{10}{\frac{\pi}{4} * D^2}[/tex]
power = [tex]{10}{\frac{\pi}{4} * (0.20*10^{-2})^2}[/tex]
power = 0.314159 kW
so
energy = power × time
669.760 = 0.314159 × time
time = 2131.9140 sec
time is 35.53 min
