Answer: Volume of 1g of pure gold [tex]v=0.05181 \mathrm{cm}^{3}[/tex]
Given;
Density of a pure gold=19.3 [tex]g / c m^{3}[/tex]
Mass of a pure gold =1g
To find:
Volume of 1g of pure gold
Solution:
According to the formula,
Density= Mass/Volume
[tex]\rho=m / v[/tex]
Where [tex]\rho[/tex]=density of pure gold
m=mass of pure gold
v=volume of pure gold
From the above equation volume can be calculated as
[tex]v=m / \rho[/tex]
Substitute the values of mass and density value in the above equation
[tex]v=1 / 19.3[/tex]
[tex]v=0.05181 \mathrm{cm}^{3}[/tex]
Result:
Thus the volume of 1g of pure gold is [tex]v=0.05181 \mathrm{cm}^{3}[/tex]
