A police car passed a truck which was traveling at 80km/h and 6 minutes (1/10 hour) later was 3 km ahead of the truck. What was the speed of the police car?

Respuesta :

Answer:

Speed of Police Car = 110 km per hr

Step-by-step explanation:

Speed of Truck S(t) = 80 km p h

Distance = speed x time

Hence distance covered by truck in [tex]\frac{1}{10}[/tex] hours

[tex]\ D(t)= \ S(t) \times  \frac{1}{10}[/tex]

[tex]\ D(t)= 80 \times \frac{1}{10}[/tex]

D(t)=8 km

Distance covered by  police car = 3 km more than that of Truck

D(c) = 8+3=11 km

Time taken = [tex]\frac{1}{10} hours[/tex]

Speed = [tex]\frac{\ Distance }{\ time}[/tex]

Replacing those values

Speed = [tex]\frac{11}{\frac{1}{10}}[/tex]

Speed = [tex]11 \times 10[/tex]

Speed = 110 kmph

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