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Narcisse and Aristide have numbers of arcade tokens in the ratio 7 : 3, respectively. Narcisse gives Aristide some of his tokens, and the new ratio is 6 : 5. What is the least number of tokens that Narcisse could have given to Aristide?

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Answer:

The least number of tokens that Narcisse could have given to Aristide are: 3

Step-by-step explanation:

Narcisse gives an "X" amount of the 7 tokens he initially had to aristide, which are added up to the 3 tokens that Aristide had. After that transaction the ratio changes from 7: 3 to 6: 5

[tex]\frac{7-X}{3+X}=\frac{5}{6}[/tex]

[tex]6*(7-X) = (X+3)*5[/tex]

42-6X=5X+15

33=11X

X=3

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