Answer:
Explanation:
Under the given situation , electron will move in two dimension, one along the plates as well as perpendicular to plates on a curved line. Time required to cover the length of plate with given velocity v and travel half the distance between the plate are equal . Initial velocity in in travelling perpendicular to plated will be zero .
Force on the electron is given by the expression
charge on electron x electric field
F = 1.6 x 10⁻¹⁹ x 9 x 10²
=14.4 X 10 ⁻¹⁷ N
Acceleration = force / mass of electron
=[tex]\frac{14.4\times10^{-17}}{9.11\times10^{-31}}[/tex]
= 1.58 x 10¹⁴ ms⁻²
If time taken to cover half the distance d = 10 cm be t
d = 1\ 2 a t²
t = √2d / a
t = [tex]\sqrt{\frac{2\times10\times10^{-2}}{1.58\times10^{14}}}[/tex]
= 3.557 x 10⁻⁸ s
If v be the velocity parallel to plate , distance travelled along plate is 50 x 10⁻² m , time taken is 3.557 x 10⁻⁸
[tex]v = \frac{50\times10^{-2}}{3.557\times10^{-8}}[/tex]
= 14.05 x 10⁶ m /s
